Toggle navigation
About
Contact
Dropdown
Action
Another action
Something else here
Nav header
Separated link
One more separated link
Trigonometry (Basic)
Home
Trigonometry (Basic)
All Questions (Page: 13)
Study Material (PDF)
All Questions (PDF)
Self Assesment
Sort As
Serial Number
Newly Added
Language
English
Bengali
Study Material (PDF)
All Questions (PDF)
Self Assesment
Sort As
Serial Number
Newly Added
Language
English
Bengali
Click on each question to see answer & solution.
Question No: #121
If `sin 2\alpha = cos \alpha`, then the value of `tan \alpha` is .......
Ans: `1/\sqrt{3}`
SEE SOLUTION
Question No: #122
If `sin 3\theta = cos (2\theta + 45^\circ)`, then the value of `tan 5\theta` is -
(a) `\sqrt{3}`, (b) `1`, (c) `\frac{1}{\sqrt{3}}`, (d) undefined
Ans: (b) `1`
SEE SOLUTION
Question No: #123
If `sin (2x+y) = cos (4x-y)`, then find the value of `tan 3x`.
Ans: `1`
SEE SOLUTION
Question No: #124
If `sin (5x-18^\circ) = cos (5y+28^\circ)`, then find the value of `x+y`.
Ans: `16^\circ`
SEE SOLUTION
Question No: #125
Prove that, `tan 7^\circ tan 23^\circ tan 60^\circ tan 67^\circ tan 83^\circ = \sqrt{3}`.
Ans:
SEE SOLUTION
Question No: #126
Prove that, `tan 15^\circ + tan 75^\circ = \frac{sec^2 15^\circ}{\sqrt{sec^2 15^\circ - 1}}`
Ans:
SEE SOLUTION
Question No: #127
Prove that, `\frac{sin 52^\circ + cos 38^\circ}{sin 38^\circ + cos 52^\circ} = tan 52^\circ`.
Ans:
SEE SOLUTION
Question No: #128
show that, `\text{cosec}^2 22^\circ cot^2 68^\circ = sin^2 22^\circ + sin^2 68^\circ + cot^2 68^\circ`.
Ans:
SEE SOLUTION
Question No: #129
Show that, `\frac{tan 57^\circ + cot 37^\circ}{tan 33^\circ + cot 53^\circ} = tan 57^\circ cot 37^\circ`.
Ans:
SEE SOLUTION
Question No: #130
Prove that, `\frac{tan 47^\circ + cot 27^\circ}{tan 43^\circ + cot 63^\circ} = cot 43^\circ cot 27^\circ`.
Ans:
SEE SOLUTION
Previous Page: 12
Next Page: 14
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15