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Trigonometry (Basic)
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Trigonometry (Basic)
All Questions (Page: 10)
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All Questions (PDF)
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Study Material (PDF)
All Questions (PDF)
Self Assesment
Sort As
Serial Number
Newly Added
Language
English
Bengali
Click on each question to see answer & solution.
Question No: #91
Prove that, `\frac{1 + cos A - sin A}{1 + cos A + sin A} = \frac{cos A}{1 + sin A}`.
Ans:
SEE SOLUTION
Question No: #92
If the angles `A` and `B` are complimentary to each other, then value of-
(i) `sin (A+B)` is ........
(ii) `\frac{1}{\text{cosec}^2 A} + \frac{1}{\text{cosec}^2 B} + \frac{1}{sin^2 (A+B)} = ` .......
(iii) `(1 - sin^2 A)(1 - cos^2 A)(1 + cot^2 B)(1 + tan^2 B) = ` ...... .
Ans: (i) `1`, (ii) `2`, (iii) `1`
SEE SOLUTION
Question No: #93
Find the complimentary angle of 63°35'15"
Ans: 26°24′45′′
SEE SOLUTION
Question No: #94
Circular value of angle supplementary to 75° angle is -
(a) `\frac{\pi}{2}^c`, (b) `\frac{3\pi}{12}^c`, (c) `\frac{5\pi}{12}^c`, (d) `\frac{7\pi}{12}^c`
Ans: (d) `\frac{7\pi}{12}^c`
SEE SOLUTION
Question No: #95
Circular value of the angle complimentary to `x°` is .........
Ans: `\pi/2 (1 - x/90)^c`
SEE SOLUTION
Question No: #96
Circular value of the angle complementary to `22.5^\circ` is -
(a) `\frac{3\pi}{8}`, (b) `\frac{\pi}{4}`, (c) `\frac{\pi}{8}`, (d) `\frac{3\pi}{4}`
Ans: (a) `\frac{3\pi}{8}`
SEE SOLUTION
Question No: #97
If `tan 22\frac{1}{2}^\circ = \sqrt{2}-1`, then the value of `cot 67\frac{1}{2}^\circ` is -
(a) `\sqrt{2}+1`, (b) `\sqrt{2}-1`, (c) `\sqrt{3}-1`, (d) `\frac{\sqrt{3}-1}{\sqrt{2}+1}`
Ans: (b) `\sqrt{2}-1`
SEE SOLUTION
Question No: #98
If `cos 27^\circ = x`, then the value of `tan 63^\circ` is -
(a) `\frac{\sqrt{1-x^2}}{x}`, (b) `\frac{x}{\sqrt{1-x^2}}`, (c) `\frac{x}{\sqrt{1+x^2}}`, (d) `\frac{x}{\sqrt{x^2-1}}`
Ans: (b) `\frac{x}{\sqrt{1-x^2}}`
SEE SOLUTION
Question No: #99
Value of `tan 15° tan 45° tan 60° tan 75°` is -
(a) `\frac{1}{\sqrt{3}}`, (b) `1`, (c) `\sqrt{3}`, (d) undefined
Ans: (c) `\sqrt{3}`
SEE SOLUTION
Question No: #100
Value of `sin 43^\circ cos47^\circ + cos43^\circ sin 47^\circ` is -
(a) `0`, (b) `1`, (c) `1/\sqrt{2}`, (d) `\sqrt{3}/2`
Ans: (b) `1`
SEE SOLUTION
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