If $ A = \begin{pmatrix} -2 & 1 & 3 \\ 0 & 4 & -1 \end{pmatrix} $ and $ B = \begin{pmatrix} 2 & 1 \\ -3 & 0 \\ 4 & -5 \end{pmatrix} $, then prove that `(AB)^T = B^TA^T`